C Programming with DSA Interview Questions for 2 Years Experience
40 questions with answers for candidates with 2 years of experience — 9 easy, 30 medium, 1 hard.
What interviewers expect: 2 years experience
At two years, you should show ownership of features and handle questions on memory leaks, undefined behaviour, bit manipulation and multi-file program design. Embedded candidates face questions on interrupts, volatile, ring buffers and protocols. DSA rounds include medium to hard problems on graphs and dynamic programming, plus basic design of small modules.
This set is weighted towards Trees and Graphs (8), Structures, Unions and File Handling (7), Linked Lists (6), Sorting, Searching and Dynamic Programming (5).
Memory safety and undefined behaviour Bit manipulation and embedded concepts Graphs and dynamic programming Module design
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A prefix sum array stores pre[i] = sum of elements from index 0 to i-1. Then the sum of any range from l to r is pre[r + 1] - pre[l] in O(1) after O(n) preprocessing. It is used for range sum queries, counting subarrays with a given sum together with a hash map, and 2D versions for matrix region sums.
Dynamic programming solves problems that have overlapping subproblems and optimal substructure by storing results of subproblems instead of recomputing them. Top-down memoisation caches recursive calls, while bottom-up tabulation fills a table iteratively. Classic examples are Fibonacci, 0/1 knapsack, longest common subsequence, coin change and edit distance. Defining the state and transition clearly is the hardest part.
03
You need to update one record in the middle of a large binary file without rewriting it all. How?
Use fixed-size records so each one starts at index times record size. Open the file in r+b mode, fseek to that offset, fwrite the new record and fflush. Read it back to verify if needed. For crash safety, write to a temporary file and rename, or keep a simple journal. Databases like SQLite solve this robustly if requirements grow.
04
A doubly linked list delete function leaves the list broken when deleting the head. What is missing?
When deleting the head there is no previous node, so the head pointer itself must move to head->next, and the new head's prev must be set to NULL. Similarly, deleting the tail needs the new tail's next set to NULL. The fix is to check node->prev and node->next for NULL and update head or tail pointers accordingly, or use a sentinel node to avoid these cases.
05
Tell me about a time you explained a complex data structure to your team.
Situation: our team needed an LRU cache in a C service and several members had not built one. Task: align everyone before coding. Action: I drew the hash table and doubly linked list on a whiteboard, walked through get and put with a small example and shared a short test suite covering edge cases. Result: the team implemented it in two days with no major review issues.
06
Your program sorts 1 crore integers in the range 0 to 999 and qsort is too slow. What would you do?
With a small known range, use counting sort: count occurrences in an array of 1000 counters, then rewrite the array in order. It runs in O(n + k) time with only 1000 extra integers, far faster than O(n log n) comparison sorts. For larger ranges, radix sort on bytes works well. qsort also pays a function call per comparison through its comparator pointer.
Height is one plus the larger subtree height.
int height(const TNode *root) {
if (root == NULL) return 0;
int lh = height(root->left);
int rh = height(root->right);
return 1 + (lh > rh ? lh : rh);
}
This counts nodes on the longest root to leaf path; return -1 for empty trees if height is defined in edges. Time O(n).
A topological sort orders the vertices of a directed acyclic graph so every edge goes from earlier to later. Kahn's algorithm repeatedly removes vertices with zero in-degree using a queue; DFS adds vertices to the order after finishing their descendants. If not all vertices are processed, the graph has a cycle. It is used for build systems, course prerequisites and task scheduling.
09
A recursive Fibonacci solution times out for n = 50. How do you fix it?
Naive recursion recomputes the same subproblems repeatedly, giving about O(1.6 to the n) calls. Memoise results in an array so each value is computed once, giving O(n), or iterate bottom-up keeping only the last two values for O(1) space. Use unsigned long long, since fib(50) exceeds the int range. Matrix exponentiation gives O(log n) for very large n.
10
Define a struct for a student and print all students with marks above 75.
Use an array of structs and the dot operator.
typedef struct {
int roll;
char name[50];
float marks;
} Student;
void printToppers(const Student *s, int n) {
for (int i = 0; i < n; i++) {
if (s[i].marks > 75.0f)
printf("%d %s %.1f\n", s[i].roll, s[i].name, s[i].marks);
}
}
Passing a const pointer avoids copying the whole array.
11
An interview asks for the minimum number of coins to make an amount. How do you approach it?
Greedy fails for some coin sets, such as coins 1, 3, 4 with amount 6, where greedy gives three coins but two coins of 3 is optimal. Use DP: dp[0] = 0 and dp[x] = 1 + min over coins c of dp[x - c], filling from 1 to the amount. Time is O(amount times coins) and space O(amount). Report -1 if the amount cannot be formed.
An adjacency matrix is a V by V array where cell [u][v] marks an edge; it gives O(1) edge checks but uses O(V squared) memory, suiting dense graphs. An adjacency list stores for each vertex a list or dynamic array of neighbours, using O(V + E) memory, which suits sparse real world graphs like road or social networks. Weighted graphs store the weight with each edge.
13
A function to insert at the head does not change the list in main. Why?
C passes arguments by value, so the function receives a copy of the head pointer; changing that copy does not affect main. Pass a pointer to the head, as in void push(Node **head, int x), and assign *head = newNode, or return the new head and assign it in the caller with head = push(head, x). This is a very common fresher interview mistake.
14
You need to find the shortest route between two cities on a map with distances. Which algorithm do you use and why?
Road distances are non-negative, so Dijkstra's algorithm with a min heap is the right choice, giving O((V + E) log V). If you only need one target, stop when it is popped from the heap. For very large maps, A star with a straight-line distance heuristic explores fewer nodes. If some edges had negative costs, Bellman-Ford would be needed.
15
Two source files both define a global variable named count and the build fails. How do you fix it?
Each global may be defined only once. Define it in one .c file, such as int count = 0;, and declare it in a shared header as extern int count;, which other files include. If the variable should be private to each file, mark it static in both files instead. Since GCC 10, -fno-common is default, so duplicate tentative definitions also fail to link.
16
What is structure padding and how can you reduce it?
The compiler inserts padding bytes between members so each one is aligned, which can make a struct larger than the sum of its members. struct { char a; int b; char c; } is usually 12 bytes instead of 6. Reduce padding by ordering members from largest to smallest alignment. Packing with __attribute__((packed)) removes padding but can slow access or fault on some CPUs.
17
Find the lowest common ancestor of two nodes in a binary search tree.
Use the BST order to walk down from the root.
TNode *lcaBST(TNode *root, int a, int b) {
while (root) {
if (a < root->key && b < root->key) root = root->left;
else if (a > root->key && b > root->key) root = root->right;
else return root;
}
return NULL;
}
The first node where a and b split is the LCA. Time O(h) and space O(1).
18
Describe how you approach a coding problem you have never seen before.
Situation: in a coding round I got an unfamiliar matrix problem. Task: solve it within 30 minutes. Action: I restated the problem, worked through a small example by hand, explained a brute force first, then spotted that a prefix sum would remove repeated work and coded it in C while talking through edge cases like empty rows. Result: I finished in 25 minutes and the interviewer praised my clear reasoning.
19
How do you check whether a linked list is a palindrome in O(1) extra space?
Find the middle with slow and fast pointers, reverse the second half in place, then compare the first half and the reversed second half node by node. Finally reverse the second half again to restore the list, which interviewers appreciate. Time is O(n) and extra space is O(1). A simpler O(n) space approach copies values into an array or stack first.
20
A hash table becomes slow as more data is inserted. What is wrong?
The load factor has grown, so chains get long or open addressing probes become long, turning O(1) into nearly O(n). Another cause is a poor hash function clustering keys into few buckets. Fix it by resizing to roughly double capacity and rehashing when the load factor crosses a threshold, and by using a better hash function. Measure the longest chain to confirm.
21
Insert a node at the end of a singly linked list using a double pointer.
A pointer to pointer handles the empty list without special cases.
int append(Node **head, int value) {
Node *n = malloc(sizeof *n);
if (!n) return -1;
n->data = value;
n->next = NULL;
while (*head) head = &(*head)->next;
*head = n;
return 0;
}
Call it as append(&head, 5). Keep a tail pointer if you append often.
22
How do you handle working with a teammate who writes buggy code?
Situation: a teammate's stack and queue module in our project kept failing tests. Task: fix the quality issue without blaming. Action: I offered to pair on one bug, showed how drawing the array and indexes revealed the off-by-one error and suggested we both add edge case tests before pushing. Result: his code quality improved quickly and our module passed all tests at the review.
A null pointer holds NULL and points to nothing; dereferencing it crashes. A dangling pointer points to memory that has been freed or a local that went out of scope. A wild pointer is uninitialised and holds a random address. A void pointer is a generic pointer that can hold any object address but must be cast before dereferencing, as malloc returns void *.
24
Why are self-balancing trees like AVL and red-black trees needed?
A plain BST can degrade to a linked list with O(n) operations when data arrives in sorted order. AVL trees keep the height difference of subtrees at most one using rotations, giving faster lookups. Red-black trees use colour rules with looser balance, so inserts and deletes need fewer rotations. Both guarantee O(log n). Red-black trees are used in the Linux kernel, C++ std::map and Java TreeMap.
25
Write a C program that counts lines, words and characters in a file.
Read character by character with fgetc.
FILE *fp = fopen(path, "r");
if (!fp) { perror("fopen"); return 1; }
long lines = 0, words = 0, chars = 0;
int c, inWord = 0;
while ((c = fgetc(fp)) != EOF) {
chars++;
if (c == '\n') lines++;
if (isspace(c)) inWord = 0;
else if (!inWord) { inWord = 1; words++; }
}
fclose(fp);
printf("%ld %ld %ld\n", lines, words, chars);
c is int so EOF can be distinguished from valid bytes.
26
What is the difference between fseek, ftell and rewind?
fseek(fp, offset, origin) moves the file position relative to SEEK_SET, SEEK_CUR or SEEK_END. ftell(fp) returns the current position as a long. rewind(fp) moves to the start and clears error flags. Together they let you find file size, jump to a record in a fixed-size record file or re-read data. For very large files, use fseeko and ftello with off_t.
27
A file opened with fopen is NULL in production but fine on your machine. How do you debug?
Always check the return value and print the reason with perror or strerror(errno), which shows errors like No such file or directory or Permission denied. Common causes are a relative path resolved from a different working directory, missing permissions for the service user, a full disk or too many open files. Use absolute or configured paths and close every file you open.
28
Count the number of islands in a grid of land and water cells. What approach do you take?
Treat each land cell as a graph node connected to its four neighbours. Scan the grid, and when you find unvisited land, increment the count and flood fill with DFS or BFS to mark the whole island visited. Time and space are O(rows times cols). For very large grids, use iterative BFS to avoid recursion depth issues, or union-find.
29
What is the difference between a declaration and a definition in C?
A declaration tells the compiler a name and its type, such as extern int count; or a function prototype, without allocating storage. A definition actually creates the object or provides the function body, such as int count = 0;. A variable can be declared many times but defined only once across the program, otherwise the linker reports a multiple definition error.
30
A program crashes with a segmentation fault. How do you find the cause?
Compile with -g and run under gdb; when it crashes, use bt to see the call stack and print variables in the failing frame. Common causes are dereferencing NULL, using freed memory, out-of-bounds array access and stack overflow from deep recursion. Building with -fsanitize=address gives a precise report of the bad access and where the memory was allocated or freed.
31
Freeing a linked list causes a crash. What is the common mistake?
A common bug is freeing the current node and then reading current->next, which is a use-after-free. Save the next pointer first, then free the node, then move on. Also make sure no node is freed twice and that the caller's head pointer is set to NULL afterwards so it is not used again. Valgrind or AddressSanitizer points to the exact line.
32
A program that writes logs with fprintf loses the last lines when it crashes. Why, and how do you fix it?
stdio streams are buffered, so fprintf stores data in memory and writes it to disk only when the buffer fills, the file closes or fflush is called. A crash loses whatever is still in the buffer. Call fflush after important log lines, set line buffering with setvbuf(fp, NULL, _IOLBF, 0) or write critical messages to unbuffered stderr. For durability on disk, add fsync on POSIX systems.
Partition around the last element, then sort both sides.
void swap(int *x, int *y) { int t = *x; *x = *y; *y = t; }
int partition(int *a, int lo, int hi) {
int pivot = a[hi], i = lo;
for (int j = lo; j < hi; j++)
if (a[j] < pivot) swap(&a[i++], &a[j]);
swap(&a[i], &a[hi]);
return i;
}
void quickSort(int *a, int lo, int hi) {
if (lo < hi) {
int p = partition(a, lo, hi);
quickSort(a, lo, p - 1);
quickSort(a, p + 1, hi);
}
}
34
How would you check whether a binary tree is a valid BST?
Comparing each node only with its children is wrong, because a deeper node can break the rule. Pass a valid range down: the left child must be in (min, node value) and the right child in (node value, max), starting with the full range of long long. Alternatively, do an in-order traversal and check values are strictly increasing. Both are O(n).
35
A loop that sums large numbers gives a negative result. What is happening?
The sum overflowed the range of int, and signed overflow in C is undefined behaviour, often wrapping to a negative value. Use a wider type like long long or int64_t for the accumulator, check before adding with a condition like if (sum > INT_MAX - x), or use compiler builtins such as __builtin_add_overflow. Compile with -fsanitize=undefined to catch it during testing.
A double pointer, such as int **pp, stores the address of a pointer. It is needed when a function must change the caller's pointer itself, for example inserting at the head of a linked list or allocating memory inside a function and returning it through a parameter. It is also used for dynamic 2D arrays and arrays of strings, like char **argv.
A function pointer stores the address of a function, declared like int (*op)(int, int) = add;, and called with op(2, 3). It enables callbacks such as the comparator in qsort, dispatch tables replacing long switch statements, plugin interfaces and state machines in embedded code. Using typedef makes function pointer types much more readable.
38
Find the length of the longest substring without repeating characters in C.
Sliding window with last seen positions.
int longestUnique(const char *s) {
int last[256];
for (int i = 0; i < 256; i++) last[i] = -1;
int best = 0, start = 0;
for (int i = 0; s[i]; i++) {
unsigned char c = s[i];
if (last[c] >= start) start = last[c] + 1;
last[c] = i;
if (i - start + 1 > best) best = i - start + 1;
}
return best;
}
For abcabcbb it returns 3.
39
You need to implement a queue using two stacks. How does it work and what is its cost?
Use an in-stack for enqueue and an out-stack for dequeue. Enqueue always pushes to the in-stack. Dequeue pops from the out-stack, and only when it is empty moves all elements from the in-stack to it, which reverses their order so the oldest comes out first. Each element moves at most twice, so operations are O(1) amortised even though a single dequeue can be O(n).
40
Write a C program to swap two numbers without using a third variable.
Using arithmetic or XOR through pointers:
void swap(int *a, int *b) {
if (a == b) return;
*a = *a ^ *b;
*b = *a ^ *b;
*a = *a ^ *b;
}
The a == b check matters because XOR swapping a variable with itself sets it to zero. In real code a temporary variable is clearer and just as fast.
Frequently asked questions
What is asked in C Programming with DSA interviews for 2 years of experience?
At two years, you should show ownership of features and handle questions on memory leaks, undefined behaviour, bit manipulation and multi-file program design. Embedded candidates face questions on interrupts, volatile, ring buffers and protocols. DSA rounds include medium to hard problems on graphs and dynamic programming, plus basic design of small modules.
How many questions should I practise before a C Programming with DSA interview?
Work through all 40 questions here, then the company-wise sets for the employers you are targeting. Quality matters more than count: be able to explain why each answer is right.
Which topics matter most for 2 years of experience?
Focus first on Memory safety and undefined behaviour, Bit manipulation and embedded concepts, Graphs and dynamic programming, Module design.