Broadcom C Programming with DSA Interview Questions & Answers
Curated interview practice questions with answers. These are practice scenarios, not a verified list of past interview questions.
About Broadcom hiring for C Programming with DSA roles
Broadcom is a global technology company that designs semiconductors for networking, broadband, wireless and storage, and also sells infrastructure software. Its software business includes VMware, CA Technologies and Symantec enterprise products acquired over the years. In India it hires chip design and verification engineers, embedded engineers and software engineers for its semiconductor and software divisions.
For C Programming with DSA roles, this Broadcom practice set focuses most on Trees and Graphs (6), Sorting, Searching and Dynamic Programming (5), Arrays and Strings (4), Pointers and Memory Management (4). It has 1 easy, 20 medium, 9 hard questions, so you can start easy and work up to the harder ones.
Company type
Hardware & semiconductors
Headquarters
Palo Alto, California, USA
Main India offices
Bengaluru, Pune, Chennai
Broadcom C Programming with DSA interview process
Online assessment or resume screening
Technical round 1 (digital design or coding)
Technical round 2 (domain depth)
Hiring manager round
Typical pattern based on public candidate experiences. Rounds vary by role, team and year.
Solved for BroadcomStart practicing
3 QUESTIONS FREESign up to unlock the full question bank and track your progress.Unlock every question and answer, then continue practising company-wise and package-wise.
Track the best sum ending here and the overall best.
long maxSubarray(const int *a, int n) {
long cur = a[0], best = a[0];
for (int i = 1; i < n; i++) {
cur = (cur + a[i] > a[i]) ? cur + a[i] : a[i];
if (cur > best) best = cur;
}
return best;
}
Input {-2, 1, -3, 4, -1, 2, 1, -5, 4} returns 6 for subarray 4, -1, 2, 1.
02
Write BFS on a graph stored as an adjacency matrix.
Use a queue and a visited array.
void bfs(int n, int adj[n][n], int start) {
int visited[n], queue[n], front = 0, rear = 0;
for (int i = 0; i < n; i++) visited[i] = 0;
visited[start] = 1;
queue[rear++] = start;
while (front < rear) {
int u = queue[front++];
printf("%d ", u);
for (int v = 0; v < n; v++) {
if (adj[u][v] && !visited[v]) {
visited[v] = 1;
queue[rear++] = v;
}
}
}
}
03
How do you check whether a linked list is a palindrome in O(1) extra space?
Find the middle with slow and fast pointers, reverse the second half in place, then compare the first half and the reversed second half node by node. Finally reverse the second half again to restore the list, which interviewers appreciate. Time is O(n) and extra space is O(1). A simpler O(n) space approach copies values into an array or stack first.
04
What is a heap and how does it implement a priority queue?
A binary heap is a complete binary tree stored in an array where every parent is smaller than its children for a min heap, or larger for a max heap. For index i, children are at 2i + 1 and 2i + 2. Insert adds at the end and sifts up, and extracting the top swaps it with the last element and sifts down, both O(log n). Building a heap from an array takes O(n).
05
An interview asks for the minimum number of coins to make an amount. How do you approach it?
Greedy fails for some coin sets, such as coins 1, 3, 4 with amount 6, where greedy gives three coins but two coins of 3 is optimal. Use DP: dp[0] = 0 and dp[x] = 1 + min over coins c of dp[x - c], filling from 1 to the amount. Time is O(amount times coins) and space O(amount). Report -1 if the amount cannot be formed.
06
A hash table becomes slow as more data is inserted. What is wrong?
The load factor has grown, so chains get long or open addressing probes become long, turning O(1) into nearly O(n). Another cause is a poor hash function clustering keys into few buckets. Fix it by resizing to roughly double capacity and rehashing when the load factor crosses a threshold, and by using a better hash function. Measure the longest chain to confirm.
A prefix sum array stores pre[i] = sum of elements from index 0 to i-1. Then the sum of any range from l to r is pre[r + 1] - pre[l] in O(1) after O(n) preprocessing. It is used for range sum queries, counting subarrays with a given sum together with a hash map, and 2D versions for matrix region sums.
08
How would you check whether a binary tree is a valid BST?
Comparing each node only with its children is wrong, because a deeper node can break the rule. Pass a valid range down: the left child must be in (min, node value) and the right child in (node value, max), starting with the full range of long long. Alternatively, do an in-order traversal and check values are strictly increasing. Both are O(n).
09
Implement union-find with path compression and union by rank.
Two small functions cover most uses.
int parent[MAXN], rnk[MAXN];
void makeSet(int n) {
for (int i = 0; i < n; i++) { parent[i] = i; rnk[i] = 0; }
}
int find(int x) {
if (parent[x] != x) parent[x] = find(parent[x]);
return parent[x];
}
int unite(int a, int b) {
a = find(a); b = find(b);
if (a == b) return 0;
if (rnk[a] < rnk[b]) { int t = a; a = b; b = t; }
parent[b] = a;
if (rnk[a] == rnk[b]) rnk[a]++;
return 1;
}
10
Find the majority element that appears more than n/2 times in O(n) time and O(1) space.
Boyer-Moore voting algorithm.
int majority(const int *a, int n) {
int cand = 0, count = 0;
for (int i = 0; i < n; i++) {
if (count == 0) cand = a[i];
count += (a[i] == cand) ? 1 : -1;
}
return cand;
}
If a majority is not guaranteed, make a second pass to count cand and confirm it exceeds n/2.
BFS explores level by level using a queue and finds the shortest path in unweighted graphs. DFS goes deep along one path using recursion or a stack, and suits cycle detection, topological sort, connected components and backtracking. Both run in O(V + E). BFS may use more memory on wide graphs, while recursive DFS can overflow the call stack on very deep graphs.
12
What is the difference between strcpy, strncpy and snprintf for copying strings?
strcpy copies until the null terminator with no bounds check, so it can overflow. strncpy limits the count but does not add a terminator if the source is too long and pads with zeros otherwise, which surprises many developers. snprintf(dst, size, "%s", src) always terminates and returns the length it wanted, so you can detect truncation. Prefer snprintf or a checked helper.
13
Your embedded device must store 10,000 sensor records in limited RAM. How would you design the struct?
Use fixed-width types sized to the real range, such as uint16_t for readings and uint32_t for timestamps, order members from largest to smallest to cut padding and pack boolean flags into bit fields or a single bitmask byte. Consider storing time as an offset from a base to save bytes. Check sizeof in a static assertion so the size stays as designed.
14
You need to implement a queue using two stacks. How does it work and what is its cost?
Use an in-stack for enqueue and an out-stack for dequeue. Enqueue always pushes to the in-stack. Dequeue pops from the out-stack, and only when it is empty moves all elements from the in-stack to it, which reverses their order so the oldest comes out first. Each element moves at most twice, so operations are O(1) amortised even though a single dequeue can be O(n).
15
You must schedule the maximum number of non-overlapping meetings in one room. What algorithm do you use?
This is activity selection, solved greedily. Sort meetings by end time, then pick each meeting whose start is not earlier than the end of the last picked one. Choosing the earliest finishing meeting always leaves the most room for the rest, which can be proven by an exchange argument. Sorting dominates, giving O(n log n) time.
16
A DP solution for a large grid uses too much memory. How can you reduce it?
Many grid DPs only need the previous row to compute the current one, so replace the 2D table with two 1D arrays or even one array updated in place, cutting memory from O(rows times cols) to O(cols). For knapsack, iterate capacity backwards in a single array. If you also need to reconstruct the path, store compact choice bits or use Hirschberg's divide and conquer technique.
17
How do you handle a situation where requirements change late in a project?
Situation: two weeks before release, the client asked to add a new field to our device's binary log format. Task: add it without breaking older files. Action: I explained the risk, added a version byte to the header, wrote a reader that handled both versions and tested with old and new samples. Result: we shipped on time and older devices kept working without a firmware update.
18
Why do linked lists perform poorly compared to arrays on modern CPUs?
Each node is allocated separately and may sit anywhere in memory, so traversing a list causes frequent cache misses and the CPU cannot prefetch well. Arrays store elements contiguously, so a cache line brings several elements at once. Even with O(1) insertion, linked lists are often slower in practice. Use them when frequent insertions in the middle with stable node addresses really matter.
Dijkstra finds shortest paths from a source in a graph with non-negative edge weights. It keeps tentative distances, repeatedly takes the unvisited vertex with the smallest distance from a min heap and relaxes its edges, updating neighbours if a shorter path is found. With a binary heap it runs in O((V + E) log V). It fails with negative weights, where Bellman-Ford is used instead.
A function pointer stores the address of a function, declared like int (*op)(int, int) = add;, and called with op(2, 3). It enables callbacks such as the comparator in qsort, dispatch tables replacing long switch statements, plugin interfaces and state machines in embedded code. Using typedef makes function pointer types much more readable.
21
Use qsort with a function pointer to sort an array of integers in descending order.
Write a comparator that returns negative, zero or positive.
int cmpDesc(const void *a, const void *b) {
int x = *(const int *)a;
int y = *(const int *)b;
return (y > x) - (y < x);
}
int arr[] = {4, 1, 9, 3};
qsort(arr, 4, sizeof arr[0], cmpDesc);
Returning y - x can overflow, so the comparison form is safer.
Quicksort is O(n log n) on average and very fast in practice with in-place partitioning, but O(n squared) in the worst case with poor pivots and not stable. Merge sort is always O(n log n) and stable but needs O(n) extra memory. Heap sort is O(n log n) worst case and in place but not stable and slower due to poor cache use. C's qsort is usually a tuned hybrid.
23
Freeing a linked list causes a crash. What is the common mistake?
A common bug is freeing the current node and then reading current->next, which is a use-after-free. Save the next pointer first, then free the node, then move on. Also make sure no node is freed twice and that the caller's head pointer is set to NULL afterwards so it is not used again. Valgrind or AddressSanitizer points to the exact line.
24
Tell me about a project where you worked with files or binary data in C.
Situation: in my final year project we logged GPS data on a microcontroller SD card. Task: store records reliably with small memory. Action: I designed a packed 16 byte record with fixed-width types, wrote it with a checksum, flushed every ten records and wrote a PC tool to decode the file. Result: we logged a full day with no corruption and could replay any trip.
25
What does sizeof return for a pointer and for an array?
sizeof on a pointer returns the size of the pointer itself, typically 8 bytes on a 64-bit system, regardless of what it points to. sizeof on an array declared in the same scope returns the total bytes of all elements, so sizeof arr / sizeof arr[0] gives the element count. Inside a function receiving an array parameter, sizeof returns pointer size, so pass the length separately.
Alignment means placing data at addresses that are multiples of its size or required boundary, such as 4 for int. CPUs read aligned data faster, and some architectures fault on misaligned access. Compilers add padding in structs to align members. You can check alignment with _Alignof and request it with _Alignas or aligned_alloc in C11.
The master theorem gives the time complexity of divide and conquer recurrences of the form T(n) = aT(n/b) + f(n). Compare f(n) with n to the power log base b of a. For merge sort, a = 2, b = 2 and f(n) = n, which match, giving O(n log n). For binary search, a = 1 and b = 2 with constant work, giving O(log n). It does not cover every recurrence.
Undefined behaviour means the C standard places no requirement on what happens, so the program may crash, give wrong results or appear to work. Examples are signed integer overflow, dereferencing a null or freed pointer, reading an uninitialised variable, accessing an array out of bounds and modifying a variable twice without a sequence point, such as i = i++. Compilers optimise assuming it never happens.
29
How do you set, clear and toggle a particular bit in C?
Use bit masks with shift operators.
x |= (1u << n); // set bit n
x &= ~(1u << n); // clear bit n
x ^= (1u << n); // toggle bit n
int bit = (x >> n) & 1u; // read bit n
Use unsigned types so shifts are well defined. These operations are common in embedded code for configuring hardware registers.
30
Count the number of islands in a grid of land and water cells. What approach do you take?
Treat each land cell as a graph node connected to its four neighbours. Scan the grid, and when you find unvisited land, increment the count and flood fill with DFS or BFS to mark the whole island visited. Time and space are O(rows times cols). For very large grids, use iterative BFS to avoid recursion depth issues, or union-find.
Tips to crack the Broadcom C Programming with DSA interview
For hardware roles, revise digital electronics, Verilog, computer architecture and verification concepts such as SystemVerilog and UVM.
For software roles, revise C, data structures, operating systems and networking, especially for VMware and infrastructure software teams.
Be ready to go deep into your project, explaining design decisions and debugging steps, as interviewers often probe details.
Keep a one-minute story ready for every project on your CV: problem, your part, tools, result.
Practise the hard questions on this page aloud; Broadcom interviewers usually ask follow-ups on your first answer.
Frequently asked questions
How many rounds are there in the Broadcom C Programming with DSA interview?
Candidates usually go through 4 stages: Online assessment or resume screening; Technical round 1 (digital design or coding); Technical round 2 (domain depth); Hiring manager round. The exact rounds change with the role, team, location and your experience, so confirm the process with the recruiter.
Which topics should I prepare for the Broadcom C Programming with DSA interview?
This practice set leans on Trees and Graphs (6), Sorting, Searching and Dynamic Programming (5), Arrays and Strings (4), Pointers and Memory Management (4). Revise those first, then practise explaining one or two of your own projects end to end, because most Broadcom interviewers ask you to walk through real work.
Are these the exact questions asked at Broadcom?
No. These are curated practice questions that match the skills and difficulty usually tested in hardware & semiconductors interviews like Broadcom's. They are not a leaked or verified list of past questions.
Where does Broadcom hire C Programming with DSA professionals in India?
Broadcom has large teams in Bengaluru, Pune, Chennai. Openings and locations change often, so check the Broadcom careers page and filter by city and experience.
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