Walmart Data Structures and Algorithms Interview Questions & Answers
Curated interview practice questions with answers. These are practice scenarios, not a verified list of past interview questions.
About Walmart hiring for Data Structures and Algorithms roles
Walmart is a global retailer operating stores and e-commerce, and it owns Flipkart and PhonePe in India. Walmart Global Tech India in Bengaluru and Chennai builds software, data and analytics solutions for Walmart's global businesses. It hires for software engineers, SDETs, data engineers, data scientists and analysts working on supply chain, pricing and customer platforms.
For Data Structures and Algorithms roles, this Walmart practice set focuses most on Heaps, Priority Queues and Greedy (5), Dynamic Programming (5), Arrays, Strings and Hashing (5), Graphs and Graph Algorithms (4). It has 1 easy, 23 medium, 6 hard questions, so you can start easy and work up to the harder ones.
Company type
E-commerce & consumer tech
Headquarters
Bentonville, Arkansas, USA
Main India offices
Bengaluru, Chennai, Gurugram
Walmart Data Structures and Algorithms interview process
Online coding assessment
Technical round 1 (DSA)
Technical round 2 (design or domain)
Hiring manager round
HR round
Typical pattern based on public candidate experiences. Rounds vary by role, team and year.
Solved for WalmartStart practicing
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01
Solve jump game: can you reach the last index if nums[i] is the maximum jump from i?
def can_jump(nums):
farthest = 0
for i, step in enumerate(nums):
if i > farthest: # this index is unreachable
return False
farthest = max(farthest, i + step)
if farthest >= len(nums) - 1:
return True
return True
# [2,3,1,1,4] -> True, [3,2,1,0,4] -> False
# Greedy: track the farthest reachable index, O(n) time, O(1) space
02
A recursive DFS in Python crashes with RecursionError on a deep input. How do you fix it?
CPython limits recursion depth to about 1000 by default. Raising the limit with sys.setrecursionlimit works for moderate depth but can crash the interpreter on very deep inputs because the C stack is limited. The reliable fix is to rewrite the DFS iteratively with an explicit stack, pushing nodes and processing them in a loop. In Java the same issue appears as StackOverflowError and has the same solution.
03
An interviewer asks you to reduce your solution's extra space from O(n) to O(1). How do you approach it?
I check what the extra structure stores and whether the input itself can hold that information. Common techniques: use two pointers instead of a hash set on sorted data, keep only the last few DP values instead of a full table, modify the input in place, such as marking visited indices by negating values, or use bit manipulation like XOR to find a missing number. I state any trade-offs, such as mutating input.
04
Given meeting start and end times for a day, how do you find the minimum number of rooms needed?
Sort meetings by start time and keep a min-heap of end times for rooms in use. For each meeting, if the earliest ending room is free by its start time, pop it; then push this meeting's end time. The heap size at the end, or its maximum, is the answer. This is O(n log n). An alternative sorts start and end times separately and sweeps with two pointers, counting overlaps.
A topological order lists the vertices of a DAG so every edge goes from earlier to later, such as an order to take courses. Kahn's algorithm computes in-degrees, pushes zero in-degree vertices into a queue and repeatedly removes them while decreasing neighbours' in-degrees; if not all vertices are output, a cycle exists. The DFS method adds a vertex to a list after visiting its descendants and reverses the list. Both are O(V plus E).
06
How is the longest common subsequence computed with DP?
Let dp[i][j] be the LCS length of the first i characters of A and the first j characters of B. If A[i-1] equals B[j-1], dp[i][j] is dp[i-1][j-1] plus 1; otherwise it is the maximum of dp[i-1][j] and dp[i][j-1]. Fill the table row by row in O(m times n) time. Backtracking from dp[m][n] recovers the actual subsequence. LCS underlies diff tools and DNA sequence comparison.
07
Design a simple scheduler that gives each job a fixed time slice in turn.
Round-robin scheduling fits a queue. Put all jobs in a FIFO queue. Repeatedly dequeue a job, run it for one time slice, and if it is not finished, enqueue it at the back with its remaining time. Each step is O(1). For priorities, keep one queue per priority level or use a priority queue. A circular buffer works well if the number of jobs is bounded, avoiding allocations.
08
You need to build a tool that shows the differences between two versions of a file line by line. What algorithm would you use?
The core is the longest common subsequence over lines: lines in the LCS are unchanged, and the rest are additions or deletions. Hash each line first so comparisons are fast. Classic LCS DP is O(m times n), which is too slow for large files, so real diff tools use Myers' algorithm, which runs in O((m plus n) times d), where d is the number of differences, fast when versions are similar.
09
Explain the sliding window technique with fixed and variable windows.
A sliding window keeps a contiguous range and updates its result incrementally instead of recomputing. A fixed window of size k, such as the maximum sum of k consecutive elements, adds the new element and removes the old one each step in O(n). A variable window grows the right end and shrinks the left end while a condition is violated, as in the longest substring without repeating characters. Both turn O(n squared) into O(n).
10
Detect whether a linked list has a cycle and return the node where the cycle begins.
def detect_cycle(head):
slow = fast = head
while fast and fast.next:
slow = slow.next
fast = fast.next.next
if slow is fast: # cycle found
slow = head
while slow is not fast: # move both one step
slow = slow.next
fast = fast.next
return slow # start of the cycle
return None
# O(n) time, O(1) space
11
How can you implement a queue using two stacks, and what is its complexity?
Use an in-stack for enqueue and an out-stack for dequeue. Enqueue pushes onto the in-stack in O(1). For dequeue, if the out-stack is empty, pop everything from the in-stack and push it onto the out-stack, which reverses the order, then pop from the out-stack. Each element moves at most once between stacks, so dequeue is O(1) amortised even though a single transfer can be O(n).
12
A report generation function loops over all users and, for each user, scans all orders. It was fine at launch but is now very slow. How do you explain and fix it?
The loop is O(users times orders), so when both grow ten times, the work grows a hundred times. I would explain this with numbers and a quick profile. The fix is to group orders by user ID once using a hash map, making the total O(users plus orders), or to push the grouping into a database query with an index. I would add a performance test with production-scale data.
13
You must build autocomplete for a search box over one million product names. Which data structure would you use?
I would use a trie where each node stores, besides children, the top few most popular completions under that prefix. Then typing a prefix walks L nodes and returns precomputed suggestions instantly, without exploring the whole subtree. Memory can be reduced with a compressed radix trie. For typo tolerance or ranking by many signals, a search engine with prefix indexes is more practical at large scale.
14
Implement topological sort using Kahn's algorithm.
from collections import deque
def topo_sort(n, edges):
adj = [[] for _ in range(n)]
indeg = [0] * n
for u, v in edges: # u must come before v
adj[u].append(v)
indeg[v] += 1
q = deque(i for i in range(n) if indeg[i] == 0)
order = []
while q:
u = q.popleft()
order.append(u)
for v in adj[u]:
indeg[v] -= 1
if indeg[v] == 0:
q.append(v)
return order if len(order) == n else [] # empty means a cycle exists
15
Compare Kruskal's and Prim's algorithms for minimum spanning trees.
Both find a minimum spanning tree, the cheapest set of edges connecting all vertices. Kruskal sorts all edges by weight and adds each edge if it joins two different components, checked with Union-Find, O(E log E); it suits sparse graphs given as edge lists. Prim grows the tree from a start vertex, always adding the cheapest edge leaving the tree using a min-heap, O(E log V), which suits dense graphs with adjacency lists.
16
You must sort a 10 GB file of records on a machine with 1 GB of RAM. How would you do it?
Use external merge sort. Read the file in chunks of about 800 MB, sort each chunk in memory and write it to disk as a sorted run, giving around 13 runs. Then perform a K-way merge: open all runs, keep a min-heap with the current record from each, repeatedly output the smallest and refill from that run, using buffered I/O. Total work is O(n log n) with roughly two passes over the data.
17
How can you reduce the space used by a DP solution?
If each row of the table depends only on the previous row, keep two rows or even a single array, reducing O(n times m) space to O(m). Fibonacci-like problems need only the last two values, so O(1). For 0/1 knapsack in one array, iterate capacity from high to low so each item is used once; for unbounded knapsack iterate low to high. The trade-off is that reconstructing the actual solution becomes harder.
Situation: I am starting my career with a strong interest in solving algorithmic and system problems. Task: grow into an engineer others rely on. Action: in the first years I want to master the codebase, deliver features reliably and deepen my skills in data structures, system design and the domain. Result: in five years I see myself as a senior engineer owning important components, mentoring juniors and contributing to design decisions in this team.
19
You have a 100 GB file of integers and only 4 GB of RAM. How would you find the duplicates?
The data does not fit in memory, so I would partition it. Read the file in streaming fashion and write each number to one of, say, 50 bucket files based on hash of the number modulo 50, so equal numbers land in the same bucket. Each bucket of about 2 GB fits in memory, where a hash set finds duplicates. Alternatively use external merge sort and scan adjacent values. A Bloom filter can pre-screen candidates.
20
Find the lowest common ancestor of two nodes in a binary tree.
def lca(root, p, q):
if root is None or root is p or root is q:
return root
left = lca(root.left, p, q)
right = lca(root.right, p, q)
if left and right: # p and q are on different sides
return root
return left or right
# O(n) time, O(h) space; assumes both nodes exist in the tree
import heapq
def merge_k_lists(lists):
heap = []
for i, node in enumerate(lists):
if node:
heapq.heappush(heap, (node.val, i, node)) # i breaks ties
dummy = tail = ListNode()
while heap:
val, i, node = heapq.heappop(heap)
tail.next = node
tail = node
if node.next:
heapq.heappush(heap, (node.next.val, i, node.next))
return dummy.next
# O(N log K) for N total nodes
22
Find the minimum number of coins needed to make an amount.
def coin_change(coins, amount):
INF = amount + 1
dp = [0] + [INF] * amount # dp[x] = min coins for amount x
for x in range(1, amount + 1):
for c in coins:
if c <= x and dp[x - c] + 1 < dp[x]:
dp[x] = dp[x - c] + 1
return dp[amount] if dp[amount] != INF else -1
# coin_change([1, 3, 4], 6) -> 2 (3 + 3)
# O(amount * len(coins)) time, O(amount) space
23
What is the diameter of a binary tree and how do you compute it efficiently?
The diameter is the number of edges on the longest path between any two nodes, which may not pass through the root. Compute it in one postorder traversal: for each node, get the heights of the left and right subtrees, update a global best with left plus right, and return 1 plus the larger height to the parent. This visits each node once, giving O(n) time instead of O(n squared) from recomputing heights.
24
Return an array where each element is the product of all other elements, without using division.
def product_except_self(nums):
n = len(nums)
out = [1] * n
prefix = 1
for i in range(n): # product of everything to the left
out[i] = prefix
prefix *= nums[i]
suffix = 1
for i in range(n - 1, -1, -1): # multiply by everything to the right
out[i] *= suffix
suffix *= nums[i]
return out
# [1,2,3,4] -> [24,12,8,6]; O(n) time, O(1) extra space besides output
25
You must merge two sorted arrays where the first array has enough empty space at the end for the second. How would you do it in place?
Merging from the front would overwrite unread elements, so merge from the back. Use three pointers: the last real element of the first array, the last element of the second, and the last slot of the first array. Repeatedly place the larger of the two candidates at the write position and move pointers left. When the second array is exhausted, the rest is already in place. This takes O(m plus n) time and O(1) space.
26
A hash map lookup in your service suddenly becomes very slow under certain traffic. What could cause it?
If many keys produce the same hash, they pile into a few buckets and operations degrade toward O(n). This can come from a poor custom hashCode, such as returning a constant or using only one field, or from attackers sending crafted keys. Fixes include a better hash function combining all fields, randomised hashing, which Python uses for strings, and tree-based buckets as in Java 8 HashMap, which caps the worst case at O(log n).
27
How do you decide between a greedy approach and dynamic programming?
Try to find a simple counterexample to the greedy rule on small inputs; if one exists, greedy is wrong and you likely need DP, which explores all choices of overlapping subproblems. If you can argue with an exchange argument that the greedy choice is always safe, greedy is simpler and faster. Coin change with arbitrary coins needs DP, while interval scheduling by earliest end time is safely greedy.
28
Find the first and last position of a target in a sorted array.
from bisect import bisect_left, bisect_right
def search_range(nums, target):
lo = bisect_left(nums, target) # first index >= target
if lo == len(nums) or nums[lo] != target:
return [-1, -1]
hi = bisect_right(nums, target) - 1 # last index <= target
return [lo, hi]
# [5,7,7,8,8,10], 8 -> [3, 4]; two binary searches: O(log n)
29
A search box must suggest the closest dictionary words when a user makes a typo. How would you approach it?
Compute edit distance between the typed word and candidate words, suggesting those within distance 1 or 2. Running O(m times n) DP against a whole dictionary is slow, so narrow candidates first using a BK-tree indexed by edit distance, a trie with bounded edit distance search, or n-gram indexes. Then rank candidates by distance and word popularity. Keyboard-aware substitution costs can improve suggestions further.
30
Implement a data structure that returns the median of all numbers added so far.
import heapq
class MedianFinder:
def __init__(self):
self.low = [] # max-heap via negation (smaller half)
self.high = [] # min-heap (larger half)
def add(self, x):
heapq.heappush(self.low, -x)
heapq.heappush(self.high, -heapq.heappop(self.low))
if len(self.high) > len(self.low):
heapq.heappush(self.low, -heapq.heappop(self.high))
def median(self):
if len(self.low) > len(self.high):
return -self.low[0]
return (-self.low[0] + self.high[0]) / 2
# add is O(log n), median is O(1)
Tips to crack the Walmart Data Structures and Algorithms interview
Think about retail problems like inventory forecasting, store replenishment and pricing, which Walmart data teams commonly work on.
Practise DSA and SQL questions together, since many roles combine coding with data handling.
Read Walmart's values of Respect for the Individual, Act with Integrity, Serve Our Customers and Strive for Excellence.
Keep a one-minute story ready for every project on your CV: problem, your part, tools, result.
Practise the hard questions on this page aloud; Walmart interviewers usually ask follow-ups on your first answer.
Frequently asked questions
How many rounds are there in the Walmart Data Structures and Algorithms interview?
Candidates usually go through 5 stages: Online coding assessment; Technical round 1 (DSA); Technical round 2 (design or domain); Hiring manager round; HR round. The exact rounds change with the role, team, location and your experience, so confirm the process with the recruiter.
Which topics should I prepare for the Walmart Data Structures and Algorithms interview?
This practice set leans on Heaps, Priority Queues and Greedy (5), Dynamic Programming (5), Arrays, Strings and Hashing (5), Graphs and Graph Algorithms (4). Revise those first, then practise explaining one or two of your own projects end to end, because most Walmart interviewers ask you to walk through real work.
Are these the exact questions asked at Walmart?
No. These are curated practice questions that match the skills and difficulty usually tested in e-commerce & consumer tech interviews like Walmart's. They are not a leaked or verified list of past questions.
Where does Walmart hire Data Structures and Algorithms professionals in India?
Walmart has large teams in Bengaluru, Chennai, Gurugram. Openings and locations change often, so check the Walmart careers page and filter by city and experience.
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