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⚡ FREE · CYLINDER + SPHERE

Thin Cylinder Calculator: Hoop Stress, Longitudinal Stress and Volume Change

Stresses, strains and volume change in thin pressure vessels, or the thickness needed.

  • 🛢️ Cylinder and sphere
  • 📏 δd, δL and δV
  • 🔧 Joint efficiency included

How to use the Thin Cylinder Stress Calculator

  1. 1. Pick the vesselThin cylinder or thin sphere, and whether you need stresses or thickness.
  2. 2. Enter the dataPressure, diameter, thickness, joint efficiencies, E and ν.
  3. 3. Read the resultsHoop and longitudinal stress, strains, and the change in volume.

Thin shell formulas

  • Hoop stress σh = pd / (2t), divided by the longitudinal joint efficiency.
  • Longitudinal stress σl = pd / (4t), divided by the circumferential joint efficiency.
  • Sphere: σ = pd / (4t) in every direction.
  • Change in diameter δd = (pd² / 2tE)(1 − ν/2).
  • Change in length δL = (pdL / 2tE)(1/2 − ν).
  • Volumetric strain = (pd / 2tE)(5/2 − 2ν) for a cylinder and 3(pd / 4tE)(1 − ν) for a sphere.

Thin-shell theory needs a thickness below about d/20. For thicker walls, use Lamé's thick cylinder equations.

Worked example and exam tips

A cylinder 3 m long and 1 m in diameter has a 15 mm wall and an internal pressure of 1.5 N/mm². E = 200 GPa and ν = 0.3. σh = 1.5 × 1000 / 30 = 50 MPa and σl = 25 MPa. δd = 0.2125 mm, δL = 0.15 mm and δV = 1.119 × 10⁶ mm³ (about 1.12 litres).

  • The hoop stress is twice the longitudinal stress, so a cylinder splits along its length.
  • Joint efficiency reduces the strength, not the strain. Use the plain-plate stresses to find δd and δV.
  • 1 MPa = 1 N/mm² = 10 bar. Keep pressure in N/mm² and lengths in mm.

Frequently asked questions

Why is hoop stress twice the longitudinal stress?

The force bursting the cylinder along its length acts over a strip of length L, while the end force acts over the smaller ring area πdt. Working this out gives pd/2t against pd/4t.

Which joint efficiency goes where?

The longitudinal seam carries the hoop stress, so its efficiency divides σh. The circumferential seam carries the longitudinal stress.

When can I use thin-cylinder theory?

When the wall thickness is less than about one-twentieth of the diameter, so the stress is nearly uniform through the wall.

Is this calculator free?

Yes. You fill in a short form once to see your result, and the other Uncodemy tools then open without it. Every calculation runs in your browser and nothing you type is sent anywhere.

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